423. 从英文中重建数字

https://leetcode-cn.com/problems/reconstruct-original-digits-from-english/

• 提交时间:2021-11-23 17:31:56
• 执行用时：16 ms, 在所有 Go 提交中击败了66.67%的用户
• 内存消耗：5.1 MB, 在所有 Go 提交中击败了24.24%的用户
• 通过测试用例：24 / 24

func originalDigits(s string) string {
    numC := map[byte]int{}
    for _, item := range s {
        numC[byte(item)]++
    }
    //0
    if co, ok := numC['z']; ok && co != 0 {
        numC['o'] -= co
    }
    //2
    if co, ok := numC['w']; ok && co != 0 {
        numC['t'] -= co
        numC['o'] -= co
    }
    //4
    if co, ok := numC['u']; ok && co != 0 {
        numC['f'] -= co
        numC['o'] -= co
    }
    //6
    if co, ok := numC['x']; ok && co != 0 {
        numC['s'] -= co
    }
    //8
    if co, ok := numC['g']; ok && co != 0 {
        numC['t'] -= co
    }
    //1
    if co, ok := numC['o']; ok && co != 0 {
        numC['n'] -= co
    }
    //3
    // if co, ok := numC['t']; ok && co != 0 {
    // }
    //5
    // if co, ok := numC['f']; ok && co != 0 {
    // }
    //7
    if co, ok := numC['s']; ok && co != 0 {
        numC['n'] -= co
    }
    //9
    // if co, ok := numC['n']; ok && co != 0 {
    // }
    ret := ""
    ret += strings.Repeat("0", numC['z'])
    ret += strings.Repeat("1", numC['o'])
    ret += strings.Repeat("2", numC['w'])
    ret += strings.Repeat("3", numC['t'])
    ret += strings.Repeat("4", numC['u'])
    ret += strings.Repeat("5", numC['f'])
    ret += strings.Repeat("6", numC['x'])
    ret += strings.Repeat("7", numC['s'])
    ret += strings.Repeat("8", numC['g'])
    ret += strings.Repeat("9", numC['n']/2)
    return ret
}